<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom" xmlns:content="http://purl.org/rss/1.0/modules/content/"><channel><title>Posts on Arnie's Blog</title><link>https://arniechan595.com/posts/</link><description>Recent content in Posts on Arnie's Blog</description><generator>Hugo</generator><language>zh-cn</language><lastBuildDate>Mon, 02 Nov 2026 00:00:00 +0000</lastBuildDate><atom:link href="https://arniechan595.com/posts/index.xml" rel="self" type="application/rss+xml"/><item><title>Hidden Knobs: What Changes When You Evaluate Rectified-Flow Image Editors Fairly</title><link>https://arniechan595.com/posts/rectified-flow-editing-evaluation/</link><pubDate>Mon, 02 Nov 2026 00:00:00 +0000</pubDate><guid>https://arniechan595.com/posts/rectified-flow-editing-evaluation/</guid><description>Editor comparisons silently vary compute, seed and operating point. Fix all three and three conclusions flip, including one of our own.</description></item><item><title>第一篇文章：公式测试</title><link>https://arniechan595.com/posts/hello-math/</link><pubDate>Mon, 02 Nov 2026 00:00:00 +0000</pubDate><guid>https://arniechan595.com/posts/hello-math/</guid><description>&lt;p&gt;行内公式：质能方程 $E = mc^2$，以及 \(a^2 + b^2 = c^2\)。&lt;/p&gt;
&lt;p&gt;块级公式：&lt;/p&gt;
$$
\int_{-\infty}^{\infty} e^{-x^2}\,dx = \sqrt{\pi}
$$$$
\sum_{n=1}^{\infty} \frac{1}{n^2} = \frac{\pi^2}{6}
$$</description></item></channel></rss>